The force/acting after time t on the bottom of a beaker of area A when water of density ρ ρ falls from a tap at a height h at uniform rate v m 3 s -1 is
A
B
C
v ρ ρ gh
D
Text Solution
Verified by ExpertsThe correct answer is:
A
Height through which water falls in time dt after t second is (h – h'), where h' is the height of water already collected.
Mass of water collected = v ρ ρ dt
and velocity of water = 
Total force = weight of water already collected + impact force
= vt ρ ρ g + v ρ ρ 2g (h – h')
= v ρ ρ 
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